Question

please answer both the questions in the attachment and don't delete my question please ​

Answer 1

Step-by-step explanation:

i) SG = NU and SN = GU (opposite sides of a parallelogram are equal)

3x = 18

\begin{array}{l} \Rightarrow \mathrm{x}=\frac{18}{3}=6 \\ 3 \mathrm{y}-1=26 \text { and } \\ \Rightarrow 3 \mathrm{y}=26+1 \\ \Rightarrow \mathrm{y}=\frac{27}{3}=9 \end{array}

x = 6 and y = 9

ii) 20 = y + 7 and 16 = x + y (diagonals of a parallelogram bisect each other)

y + 7 = 20

⇒ y = 20 - 7 = 13 and,

x + y = 16

⇒ x + 13 = 16

⇒ x = 16 - 13 = 3

x = 3 and y = 13

Answer 2

solution of B)

hope it hepls u....!