Question

please answer briefly
I will mark as brainiest​

Answer 1

Answer:

• Gravitational force on the 1 kg object placed on the earth's surface will be 9.77 Newton

Explanation:

Given,

• mass of object (placed on earth surface) , m = 1 kg
• mass of earth, M = 6 × 10²⁴ kg
• radius of earth, R = 6.4 × 10⁶ m

we need to find,

• Magnitude of the gravitational force between Earth and the 1 kg object , F = ?

Formula we need to use is,

• F = G m M / R²

[ where F is the gravitational force between two objects of masses m and M ; R is the distance between the two objects (In this question R is the distance between centre of earth and earth's surface which is giving the distance between earth and the object) ; G is the universal gravitational constant ]

so,

Using formula

→ F = G m M / R²

[ putting given values and G = 6.7 × 10⁻¹¹ N kg⁻² m² ]

→ F = (6.67 × 10⁻¹¹) (1) (6 × 10²⁴) / (6.4 × 10⁶)²

→ F = 6.67 × 6 × 10¹³ / (6.4 × 6.4 × 10¹²)

→ F = 40.02 × 10¹³ / ( 40.96 × 10¹² )

→ F = 9.77 Newton

therefore,

• Gravitational force on the 1 kg object placed on the earth's surface will be 9.77 Newtons .(approx.)