Question

please answer by solving​

Answer 1

$\huge\bigstar \underline\mathfrak \color{aqua}Answer \: :$

$\qquad \quad {\boxed{ \sf{\color{deeppink}{\rightarrow \:( c)Rs \: 642}}}}$

$\huge\bigstar \underline\mathfrak \color{lime}Explanation \::$

☆To find :-

The cost price of the item.

☆Given :-

Selling price = Rs 749 and gain = 1/6 of cost price

☆Formula use :-

${\boxed{\sf{\color{violet}{CP+gain=SP}}}}$

☆Assuming:-

Let the cost price be x

☆Solution:-

According to question a shopkeeper sells an item for Rs 749 and gain one sixth of cost price .

Now,CP= x ,gain = x/16 and SP= 749

Now,putting the values in the formula, we have

$\sf \Rightarrow x \: + \frac{x}{6} = 749 \\ \\ \sf \Rightarrow \frac{6x + x}{6} = 749 \\ \\ \sf \Rightarrow \frac{7x}{6} = 749 \qquad \\ \\ \sf \Rightarrow \: 7x = 749 \times 6 \\ \\ \sf \Rightarrow \: x = \frac{749 \times 6}{7} \\ \\ \sf \Rightarrow \color{red}x = 642\qquad$

$\therefore \color{yellow} \sf \: The \: cost \: price = Rs \: 642$

☆Hence :-

Cost price = Rs 642

☆Verification:-

By solving we get CP = Rs 642

Given,Gain =1/6th of CP

Therefore, gain= Rs642/6=Rs107

We know,SP = CP+Gain

Therefore, SP=Rs(642+107)=Rs749,which is equal to the given SP in the question.

Hence proved

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☆Extra information:

• Profit, P = SP – CP; SP>CP

• Loss, L = CP – SP; CP>SP

• P% = (P/CP) x 100

• L% = (L/CP) x 100

• SP = {(100 + P%)/100} x CP

• CP = {100/(100 + P%)} x SP

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hope it helps ...... :)