Question

please answer by solving​

Answer 1

Answer:

Here the question is saying that If the area of a square is 50m², then find the sum of length of its both diagonals.

Step-by-step explanation:

Using the formula for the area of a square, A= 50 = s^2.

2. Using Pythagorean theorum, s^2 + s^2 = d^2.

3. combining equations by substituting the first into the second twice says 50 + 50 = d^2.

4. solving, then 100 = d^2 gives d=10.

Answer 2

$\large\mathscr \color{black}\colorbox{red}{\colorbox{orange}{\colorbox{yellow}{\colorbox{green}{\colorbox{blue}{\colorbox{indigo}{\colorbox{violet}{\underline {ANSWER}}}}}}}}$

$\tt{area \: of \: square = {a}^{2}} = \tt50 {cm}^{2} \\ \\ \tt a = \sqrt{50 {cm}^{2} } \\ \tt a = \sqrt{50} cm \\ \\ \tt \color{pink}diagonal = \sqrt{ 2{a}^{2} } \\ = \tt\sqrt{2 ({ \sqrt{50} }^{2} )} = \sqrt{2 \times 50} \\ \tt = \sqrt{100} = 10cm \\ \\ \tt \color{pink} sum \: of \: its \: two \: diagonals \\ = \tt10cm + 10cm \\ = \tt \color{lime}\underline{ \underline{20cm}}$