please answer circle one
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Answer to question.8
by using the angle relationship for angle>90°
sec(theta)=cosec(90-theta) and vice-versa
so,
sec(5a)=cosec(a-30)
=> cosec(90-5a)=cosec(a-30)
on comparing,,
(90-5a)=a-30
120=6a
a=20°
by using the angle relationship for angle>90°
sec(theta)=cosec(90-theta) and vice-versa
so,
sec(5a)=cosec(a-30)
=> cosec(90-5a)=cosec(a-30)
on comparing,,
(90-5a)=a-30
120=6a
a=20°
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