Question

please answer..class 11​

Answer 1

Step-by-step explanation:

A has The natural numbers more than equal to 2 upto less than equal to 6

A = { 2, 3, 4, 5, 6}

B has prime numbers less than or equal to 7

B = {2 3 5 7}

C = x^2 - 5x + 6=0

x^2 -2x - 3x + 6=0

x(x -2) - 3(x-2)=0

(x - 3)(x-2) = 0

x = 3 , 2

C = {2, 3}

b) AUB = {2 3 4 5 6 7} UC = {2 3 4 5 6 7} as C contains common members which are already there in AUB

BUC = { 2 3 5 7}

A U {2 3 5 7} =.{2 3 4 5 6 7}

Hence LHS = RHS proved