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CORRECT ANSWER WILL BE MARK AS BRAINLIST

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Answer 1

Answer:

HEY MATE HERE'S YOUR ANSWER!

1 Velocity of sound in water,

v= 2d/t

v= 2 x 3625/5 

v= 1450 ms-1

2.Distance of hill from the man

D1 = velocity x time/ 2 = v × 5 / 2----------------- (equation 1)

Now, D1 − 310 = v × 3 / 2--------------------------- (equation 2)

By subtracting equation 2 form equation 1 ,

we get 310 = v x (5/2 − 3/2)

So, v = 310m/s

3.When he walks 85 m towards the cliff then the echo of a second shot is now heard after 1.5 second. So it is clear that:

in 1/41/4 sec the round travel=85=85m

SO, in 1 sec, sound travel =4×85=340=4×85=340 m

4.A = 1.0 cm. l = 0.70 m/4 = 0.18 m

HOPE IT HELPS YOU:)

Answer 2

Answer:

ok

Explanation:

my name is freny

I m from gujarati

I study in 8 th