Question

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Answer 1

Answer:

Explanation:

x = 5 sin2πt

velo v = dx/dt = 5 cos2πt x 2π = 10π cos2πt

velo at t = o.25 s is  

v = 10π cos2πx0.25

  = 10π cosπ/2

  = 0

Since the particle is executing SHM

Compare given eqn with x = A sinωt

∴ ω = 2π

⇒ 2πf = 2π

Time period T = 1/f = 1 sec  

∴ In time interval t = 0 s and t = 1 s {i.e 1 time period} the

Change in displacement = 0

∴ Average velocity = 0

Answer 2

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