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1) B
2)A
3)A
4)D
5)B
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Question given :
If ∆ ABC is congruent to ∆ PQR then line segment AB corresponds to
- PQ
- QR
- RP
- PR
∆QRS is congruent to
- ∆ TPQ
- ∆ PQT
- ∆ QTP
- ∆ QPT
∆ ABC is congruent to ∆ PQR w.r.t the axiom of
- ASA
- SAS
- SSS
- RHS
Required solutions :
If ∆ ABC is congruent to ∆ PQR then line segment AB corresponds to PQ
Note : Refer to the attached figure
▬▬▬▬▬▬▬▬▬▬▬▬▬▬
∆QRS is congruent to TPQ
Corresponding parts ,
- TP = QR
- PQ = RS
- TQ = QS
- Angle QPT = Angle QRS
- Angle QTP = Angle RQS
▬▬▬▬▬▬▬▬▬▬▬▬▬▬
∆ ABC is congruent to ∆ PQR w.r.t the axiom of ASA
Two angles along with one side are equal
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