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Answer:
1.B
2.50°(a)☺️☺️☺️☺️☺️☺️☺️☺️
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Question given :
In ∆ABC if BC² + AB² = AC² , then the right angle is at _____
- A
- B
- C
- Does not exist
In the given figure AB is parallel to CD if angle APQ = 70 and angle PRD = 120 then angle QPR =
- 50°
- 60°
- 40°
- 35°
Required solutions :
In ∆ABC if BC² + AB² = AC² , then the right angle is at B point .
Reasoning :
Pythagoras theorem has been used here the hypotenuse is AC , AB and BC are legs and the triangle is right angled at B
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In the given figure AB is parallel to CD if angle APQ = 70 and angle PRD = 120 then angle QPR = 50
Reasoning :
- If Angle APQ = 70 then angle PQR is also 70° by alternate interior angle property ,
- If angle PRD = 120 then angle PRQ would be ,
- Angle PRQ + Angle PRD = 180°
- Angle PRQ = 180 - 120
- Angle PRQ = 60°
- By linear pair property
- Now by angle sum property we get ,
- Angle PRQ + angle PQR + angle QPR = 180°
- 60° + 70° + Angle QPR = 180°
- 130° + Angle QPR = 180°
- Angle QPR = 180° - 130°
- Angle QPR = 50°
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