Question

please answer correctly...​

Answer 1

Answer:

The requirement of the ques in how many ways we can differ the molecule $\ C_{6}H_{14}$.

》This means how many structural isomers can be possible for $\ C_{6}H_{14}$.

》First check the degree of unsaturation(DU) of the molecule.

$\boxed{\bf{DU = x+1 - \dfrac{y}{2}}}$

where 'x' is no. of carbon atoms and 'y' is no. of hydrogen atoms.

》DU = 6+1 - (14/2)

• DU = 7-7 = 0

means there is no double/triple bond present, it is an saturated compound.

》refer the above image! for no. of structures.

☆There are 5 possible ways,5 structural isomers are can be obtained of given molecule.

Answer 2

Explanation:

Answer:

The requirement of the ques in how many ways we can differ the molecule $\ C_{6}H_{14}$.

》This means how many structural isomers can be possible for $\ C_{6}H_{14}$.

》First check the degree of unsaturation(DU) of the molecule.

$\boxed{\bf{DU = x+1 - \dfrac{y}{2}}}$

where 'x' is no. of carbon atoms and 'y' is no. of hydrogen atoms.

》DU = 6+1 - (14/2)

• DU = 7-7 = 0

means there is no double/triple bond present, it is an saturated compound.

》refer the above image! for no. of structures.

☆There are 5 possible ways,5 structural isomers are can be obtained of given molecule.