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Answers
Answer :
The speed of rowing in still water is 7 km/hr and the speed of the current is 3 km/hr.
Explaination :
Let :
➺ Speed of her in still water be u km/hr.
➺ Speed of current be v km/hr.
We know that :
➺ Speed downstream = u + v
➺ Speed upstream = u — v
Given, she can row downstream 30 km in 3 hrs.
➺ Speed = Distance/Time
➺ u + v = 30/3
➺ u + v = 10 km/hr
Also, she can row upstream 12 km in 3 hrs.
➺ Speed = Distance/Time
➺ u — v = 12/3
➺ u — v = 4 km/hr
Here, the pair of linear equations in two variables are :
➺ u + v = 10 . . . . . ⓵
➺ u — v = 4 . . . . . ⓶
From, ⓵ we get the value of ‘u’ as :
➺ u + v = 10
➺ u = 10 — v
Substituting this value of ‘u’ in ⓶ :
➺ u — v = 4
➺ (10 — v) — v = 4
➺ 10 — 2v = 4
➺ — 2v = 4 — 10
➺ — 2v = — 6
➺ v = — 6/— 2
➺ v = 3 km/hr
Substituting the value of ‘v’ in ⓵ :
➺ u + v = 10
➺ u + 3 = 10
➺ u = 10 — 3
➺ u = 7 km/hr
Therefore, the speed of rowing in still water is u = 7 km/hr and the speed of the current is v = 3 km/hr.
Answer:
u is equal to 7
v is equal to 3.
Step-by-step explanation:
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