Question

please answer correctly​

Answer 1

Solution:

sum of zero

α+β=-b/a

product of zero

αβ=c/a

now,

α+β=-b/a  and

αβ=1/a

then,

${a}^2$+$B^2$=$(a+B)^2$

$(a+B)^2=(\frac{-b}{a} )^2$

∴$a^2+B^2=\frac{-b^2}{a^2}$