please answer correctly and explain.
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qpr=50
pq=pr(tangents of a circle)
pqr=pqr(angle opp to equal sides are equal)
now,
in∆pqr
qpr+pqr+prq=180(angle sum property of a ∆)
50+pqr+pqr=180
2pqr=180-50
2pqr=130
pqr=130/2
pqr=65
now,
oqp=90(line drawn from the centre to the tangent is perpendicular)
oqr=oqp-pqr
oqr=90-65
oqr=25
pq=pr(tangents of a circle)
pqr=pqr(angle opp to equal sides are equal)
now,
in∆pqr
qpr+pqr+prq=180(angle sum property of a ∆)
50+pqr+pqr=180
2pqr=180-50
2pqr=130
pqr=130/2
pqr=65
now,
oqp=90(line drawn from the centre to the tangent is perpendicular)
oqr=oqp-pqr
oqr=90-65
oqr=25
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