Question

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Answer 1

Question :-

If :-

• P = 3x² - 5x + 2
• Q = 11x² + 3x - 1
• R = 5x² - 5x + 7

Find :-

P + ( Q - R )

Answer :-

The value of P + ( Q - R ) is 9x² - 2x + 8.

Step-by-step explanation :-

$\mapsto \bf{P + ( Q - R )} \\ \\ \\ \mapsto \: \sf{{3x}^{2} - 5x + 2 + ( {11x}^{2} + 3x - 1 - {5x}^{2} - 5x + 7)} \\ \\ \\ \mapsto \: \sf{{3x}^{2} - 5x + 2 + ( {11x}^{2} + {5x}^{2} + 3x - 5x - 1 + 7)} \\ \\ \\ \mapsto \: \sf{{3x}^{2} - 5x + 2 + {6x}^{2} + 3x + 6} \\ \\ \\ \mapsto \: \sf{{3x}^{2} + {6x}^{2} - 5x + 3x + 2 + 6} \\ \\ \\ \mapsto \: \bf{\pink{{9x}^{2} - 2x + 8}} \: \: \: \bigstar$

Hence,

The value of P + ( Q - R ) is 9x² - 2x + 8.

Now, Verification

$\mapsto \bf{P + ( Q - R ) = 9x² - 2x + 8} \\ \\ \\ \mapsto \: \sf{{3x}^{2} - 5x + 2 + ( {11x}^{2} + 3x - 1 - {5x}^{2} - 5x + 7) =9x² - 2x + 8 } \\ \\ \\ \mapsto \: \sf{{3x}^{2} - 5x + 2 + ( {11x}^{2} + {5x}^{2} + 3x - 5x - 1 + 7) = 9x² - 2x + 8} \\ \\ \\ \mapsto \: \sf{{3x}^{2} - 5x + 2 + {6x}^{2} + 3x + 6 =9x² - 2x + 8 } \\ \\ \\ \mapsto \: \sf{{3x}^{2} + {6x}^{2} - 5x + 3x + 2 + 6 =9x² - 2x + 8 } \\ \\ \\ \mapsto \: \sf{{9x}^{2} - 2x + 8 =9x² - 2x + 8 }$

L.H.S = R.H.S

HENCE, VERIFIED !!