Question

please answer correctly!!

calculate the average molar mass of a gaseous mixture weighing 360g and containing 3.011 × 10^24 molecules of N2O ,2.5 gram molecules of N2 and also certain mass of Ethene C2 H4​

Answer 1

Answer:

20g of Al = 20/26.98 mol = 0.74 mol

30g of S = 30/32.07 mol = 0.94 mol

so, only min(.74/2,.94/3) = 0.31333 mol of Al2S3 can be formed:

.31333 mol Al2S3 = .61667*26.98g Al + .94*32.07 g S = 16.64g Al + 30g S

That leaves 3.36g Al unreacted6 by fhyrh hu dozoo xxxii do soCo xxxii DJ Di dogo do Fu fighting for you guys