Question

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Answer 1

Step-by-step explanation:

$6 {tan}^{2} \alpha - \frac{6}{ {cos}^{2} \alpha } \\ \\ = 6( {tan}^{2} \alpha - \frac{1}{ {cos}^{2} \alpha } ) \\ \\ = 6( {tan}^{2} \alpha - {sec}^{2} \alpha ) \\ \\ = 6 \times 1 \\ \\ = 6 \\ \\ \\ \\ using \: formula \: \frac{1}{cos \: a} = sec \: a \\ \\ {tan}^{2} a - {sec}^{2} a \: = 1$