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Corner points of the feasible region determined by the system of linear constraints are (0, 3), (1, 1) and (3, 0). Let z = px + qy, where p, q> 0. Condition on p and q so that the minimum of z occurs at (3, 0) and (1, 1) is
1) p = 2q 2) p = q/2 3) p = 3q 4) p = q
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Answered by
17
Answer:
your answer is p=q/2
Step-by-step explanation:
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Answered by
11
Step-by-step explanation:
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q/2 is ansr
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