Question

please answer correctly
if a 1200 W electronic iron is used fault for 30 minutes then how much energy will be consumed in the month of April​

Answer 1

Answer:

Explanation:

Given that,

Power =1200W=1.2kWh

Time = 30 min / day × 30 days =0.5h×30= 15 h

Energy =Power×Time=1.2×15= 18kWh.