Question

please answer correctly

Water at a pressure of 4 X 10^4 Nm^-2 flows at 2ms^-1 through a pipe of 0.02m² cross sectional area which reduces to 0.01m². What is the pressure in the smaller cross section of the pipe?​

Answer 1

Answer:

34000 Pa

Explanation:

A1V1=A2V2

(0.02)(2)=(0.01)V2

V2=4 m/s

Now apply Bernoullis theorem

P+21PV2+ρgh= constant

here h=0, so formula will be

P1+2ρV1=P2+2ρV22−−−−−(1)

P1=40000 Pa,V1=2,V2=4,P=1000 kg/m3

Putting values in eq (1)

P2=34000 Pa