Math, asked by riya15042006, 5 months ago

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Answered by kimtaehyung83
2

Answer:

In right angle triangle ACB,

AB^2 =AC^2 +BC^2 =(12)^2 +(16)^2

=144+256=400

AB= √400 =20m=Diameter

Radius = 20/2 =10m

Arc length ACB = 1/2×2πr=1/2×2×3.142×10=31.42m

Perimeter of shaded region =31.42+12+16=59.42cm

Area of shaded region = 1/2πr^2-1/2×AC×CB=1/2(3.142×10^2-12×16)

= 1/2×(3.142-192)= 1/2×122.2=61.1cm^2

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hope it helps you

Answered by rashmitamishtiroy
2

Answer:

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