Question

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Answer 1

Answer:

In △ABC,∠A=90°

By Pythagoras theorem,

BC^2 =AB^2+AC^2

3^2+4^2

9+16=25

∴BC=5cm

A(shadded region)=A(△ ABC)+A (semicircle AB) + (semicircle AC) - A(semicircle BAC)

= 1/2×3×4+1/2×π(3/2)^2+1/2×π(4/2)^2-1/2×π(5/2)^2

= 6+6π/8+2π-25π/8

= 6+2π−2π

=6 cm^2

Step-by-step explanation:

hope it helps you

Answer 2

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