Question

please answer explain ​

Answer 1

Given :

• DA $\perp$ AB
• CB $\perp$ AB
• AC = BD

Need To Show :

• $\triangle$ ABC = $\triangle$ BAD

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

❍ Showing $\triangle$ ABC = $\triangle$ BAD

⠀⠀⠀⠀ In $\triangle$ ABC and $\triangle$ BAD

• $\angle$ A = $\angle$ B ⠀⠀⠀⠀ ..[ Right Angle , Both 90⁰ ]

• AB = BA ⠀⠀⠀⠀ ..[ Common Side ]

• AB = DB ⠀⠀⠀⠀ ..[ Hypotenuse, Given ]

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm { \bf{\triangle ABC \cong \triangle BAD \quad \longrightarrow\:\:[ By \:R.H.S \:Congruency \:rule] }}}}$

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀