Question

please answer .. factorisation ​

Answer 1

Step-by-step explanation:

plz solve this further by u

I gave hint u

Answer 2

Step-by-step explanation:

Solution :-

9)

Given expression is (x - 1/x)^2+6 (x - 1/x) +9

Let a = (x - 1/x) then

=> a^2+6a+9

=> (a)^2+2(a)(3)+(3)^2

It is in the form of a^2+2ab+b^2

We know that

(a+b)^2 = a^2+2ab+b^2

=> (a)^2+2(a)(3)+(3)^2

=> (a+3)^2

=> (a+3)(a+3)

=> ( x - 1/x +3) ( x - 1/x -3)

(x - 1/x)^2+6 (x - 1/x) +9 = ( x - 1/x +3) ( x - 1/x -3)

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10)

Given expression is 64x^6 - 729y^6

=> 2^6 x^6 - 3^6 y^6

=> (2x)^6 - (3y)^6

=>[(2x)^3]^2 - [(3y)^3]^2

It is in the form of (a+b)(a-b)

Where a = (2x)^3 and b = (3y)^3

We know that

(a+b)(a-b)= a^2-b^2

=> [(2x)^3]^2 - [(3y)^3]^2

=> [(2x)^3+(3y)^3] [(2x)^3-(3y)^3]

=> (2x+3y)(4x^2-6xy+9y^2)(2x-3y)(4x^2+6xy+9y^2)

=>(2x+3y)(2x-3y)(4x^2+6xy+9y^2)(4x^2-6xy+9y^2)

Since ,a^3+b^3 = (a+b)(a^2-ab+b^2)

a^3-b^3 = (a-b)(a^2+ab+b^2)

64x^6 - 729y^6=

(2x+3y)(2x-3y)(4x^2+6xy+9y^2)(4x^2-6xy+9y^2)

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Used formulae:-

• a^3-b^3 = (a-b)(a^2+ab+b^2)

• a^3+b^3 = (a+b)(a^2-ab+b^2)

• (a+b)(a-b)=a^2-b^2

• (a+b)^2 = a^2+2ab+b^2

• (a-b)^2 = a^2-2ab+b^2