Question

please answer fast 1+cos a /sec a-tan a - 1-cos a / seca+tana=2(1+tana) prove ​

Answer 1

Answer:

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Answer 2

$\frac{1 + cosa}{seca - tana} - \frac{ 1 - cosa}{seca + tana} \\ \\ = \frac{cosa(1 + cosa)}{1 - sina} - \frac{cosa(1 - cosa)}{1 + sina} \\ \\ = cosa( \frac{1 + sina + cosa + sinacosa - 1 + sina + cosa- sinacosa}{1 - {sin}^{2}a } ) \\ \\ = \frac{2(sina + cosa)}{cosa} \\ \\ = 2(1 + tana)$