Question

Please answer fast.......................

Answer 1

Answer:

first construction a line EF parallel to CD (see the attachment).

now ,

angle abo and angle boe are supplementary angles.

so , 55° + angle boe = 180°

=> angle boe = 180 - 55

=> angle boe = 125° ---- (i)

similarly,

angle cod + angle eod = 180°

=> 25° + angle eod = 180°

=> angle eod = 180° - 25°

=> angle eod = 155° ---- ( ii )

now , adding ( i ) and ( ii ) , we get

125° + 155°

=280°

so , angle x = 280°

hope it helps...

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