Question

PLEASE ANSWER FAST ​

Answer 1

Answer:

Explanation:

The rotational inertia of a circular object is,

$I = mr^2$

So, the rotational inertia of semicircle will be,

$I= m(\frac{r^2}{2})$

The radius of the semicircle can be derived using the formula that,

lenght of axis  joining free ends of semiconductors =  circomference of semi conductor

So let the length of the axis which is joining free ends of semicircle be l.

So the radius of semicircle will be,

$l =\pi r$

$r = \frac{1}{\pi }$

$I= m(\frac{i^{2} }{2\pi ^{2} } )$

OPTION C IS CORRECT

Answer 2

Answer:

option c

Explanation:

hope it helps you