Question

please answer fast. ​

Answer 1

Answer:

k ≠ 6

Explanation:

Given equations:

kx + 2y = 5

3x + y = 1

$\frac{a1}{a2} \neq \frac{b1}{b2}$  ⇒unique solution

$\frac{k}{3} \neq \frac{2}{1}$    .........[by cross multiplication]

k ≠ 6

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