Math, asked by THARUNPRAKASH, 9 months ago

please answer fast

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Answered by anshikaverma29
1

(\frac{a}{b})^4*( \frac{4ab}{3a})^2*(\frac{b}{2a})^3\\  \\=[\frac{a^4}{b^4}*\frac{16a^2b^2}{9a^2}]*\frac{b^3}{8a^3}\\   \\=[\frac{16a^4}{9b^2}*\frac{b^3}{8a^3}]\\  \\=\frac{2ab}{9}

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