Question

please answer...fast

Answer 1

Hi,

Given time taken by two types to

fill the tank = 9 3/8 hr = 75/8 hours

Part of two taps to fill the tank in 1 hr

= 1/(75/8) = 8/75

Let the time taken by less diameter tap to fill the tank be x hours.

Let the time taken by more diameter

tap to fill the tank = ( x - 10 ) hours

Part of less diameter tap to fill the tank in 1 hour = 1/x

Part of more diameter tap fill the the

tank in 1 hour = 1/( x - 10 )

Part of two taps fill the in 1 hour = 8/75

1/x + 1/(x - 10 ) = 8/75

( x - 10 + x ) / [ x ( x - 10 )] = 8/75

( 2x - 10 )75 = 8( x² - 10x )

150x - 750 = 8x² - 80x

8x² - 80x - 150x + 750 = 0

8x² - 230x + 750 = 0

8x² - 200x - 30x + 750 = 0

8x( x - 25 ) - 30( x - 25 ) = 0

( x - 25 ) ( 8x - 30 ) = 0

x - 25 = 0 or 8x - 30 = 0

x = 25 or x = 30/8 = 15/4

Time taken by small tap to fill the tank = x = 25 hours

Time taken by big tap to fill the tank

= x - 10

= 25 - 10

= 15 hours

I hope this helps you.

:)