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consider ∠CAD = ∅
∴∠CDA = ∅+22° & ∠ACD = ∅+26°
∅+26° + ∅+22° + ∅ = 180°
∅ = 44°
∴∠CAD = 44°, ∠CDA = 66°, ∠ACD = 70°
∠CBD = 44° + ∠BDA
from ΔBEC and ∠BCE + ∠BDA =26°
∠BCE + x+80+44° + ∠BDA = 180°
x= 30°
∴∠CDA = ∅+22° & ∠ACD = ∅+26°
∅+26° + ∅+22° + ∅ = 180°
∅ = 44°
∴∠CAD = 44°, ∠CDA = 66°, ∠ACD = 70°
∠CBD = 44° + ∠BDA
from ΔBEC and ∠BCE + ∠BDA =26°
∠BCE + x+80+44° + ∠BDA = 180°
x= 30°
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