Question

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Answer 1

hey mate here is your answer

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Answer 2

$\huge\mathcal{Question}$

$i \: \: think \: \: in \: your \: question \: \: something \: \: is \: \: missing \: \:$

So, let me complete it ....

$(x + \frac{1}{x} ) = 2 + \sqrt{3} \\ find \: \: {x}^{2} + \frac{1}{ {x}^{2} }$

$use \: this \: linear \: propert y$

${(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab$

$\huge\mathcal\blue{AnsWeR}$

${(x + \frac{1}{x} }^{2} ) \\ = {x}^{2} + \frac{1}{ {x}^{2} } \\ + 2 \times x \times \frac{1}{x}$

$(2 + \sqrt{3} ) \\ = {x}^{2} + \frac{1}{ {x}^{2} } + 2$

$as \: opposite \: \\ signs \: are \: cancelled \\ \: so \: + 2 \: and \: - 2 \: \\ will \\ \: get \: cancelled \:$

$\sqrt{3} = {x}^{2} + \frac{1}{ {x}^{2} }$

Here is your answer....

Hope it helps....