Question

please answer fast.. ​

Answer 1

Answer:

Step-by-step explanation:

kx²+2x-3=0

x=2

k(2)²+2×2-3=0

4k+4-3=0

4k+1=0

k=-1/4

Answer 2

Given :–

• An equation = kx² + 2x – 3 = 0.
• Where, x = 2.

To Find :–

• The value of k.

Solution :–

Given equation is,

• kx² + 2x – 3 = 0

And

• x = 2

Now, substitute the value of x in the given equation.

$\mapsto k {(2)}^{2} + 2 (2) - 3 = 0$

$\mapsto k(4) + 2(2) - 3 = 0$

$\mapsto k \times 4 + 2 \times 2 - 3 = 0$

$\mapsto 4k + 4 - 3 = 0$

$\mapsto 4k + 1 = 0$

$\mapsto 4k = - 1$

$\mapsto k = \dfrac{ - 1}{4}$

Hence,

The correct option is (c) k = -1/4.

Verification :–

Substitue all the values in the given equation.

We have,

• x = 2
• k = $k = \dfrac{ - 1}{4}$

$\mapsto \dfrac{ - 1}{4} \times 2 + 2(2) - 3 = 0$

$\mapsto \dfrac{ - 1}{\cancel{4}} \times \cancel2 + 4 - 3 = 0$

$\mapsto \dfrac{ - 1}{2} \times 1 + 1 = 0$

$\mapsto \dfrac{ - 1 + 1}{2} = 0$

$\mapsto \dfrac{0}{2} = 0$

$\mapsto 0 = 0$

Hence Verified !!