Question

Please answer fast ​

Answer 1

Step-by-step explanation:

HERE, THE PRINCIPLE IS ₹1500.

SIMPLE INTEREST= ₹80

RATE= 8% per annum

SO, TIME PERIOD= SI ×100/R×P

= 80×100/8×1500

= 10/15= 2/3 yrs × 12 months = 8 months

8 MONTHS IS YOUR ANSWER

Answer 2

$\pink{ \frak{Given}} \begin{cases} \sf \: Principal \: (P) = Rs. 1500 \\ \\ \sf \: Rate \: (R) = 8 \% \\ \\ \sf \: Simple \: Interest \: (SI) = Rs. 80 \\ \\ \sf \: Time \: (T) =? \end{cases}$

☯$\underline{\boldsymbol{According\: to \:the\: Question:}}$

$: \implies \displaystyle \sf \: Time \: (T) = \frac{100 \times SI}{P \times R}$

$: \implies \displaystyle \sf \: Time \: (T) = \frac{100 \times 80}{1500 \times 8}$

$: \implies \displaystyle \sf \: Time \: (T) = \frac{8000}{1500 \times 8}$

$: \implies \displaystyle \sf \: Time \: (T) = \frac{1000}{1500}$

$: \implies \displaystyle \sf \: Time \: (T) = \frac{10}{15}$

$: \implies \underline{ \boxed{\displaystyle \sf \: Time \: (T) = \frac{2}{3} \: years}}$

___________________…

$\\ \dashrightarrow \displaystyle \sf \: Time \: (T) = \frac{2}{3} \: years$

$\dashrightarrow \displaystyle \sf \: Time \: (T) = \frac{2}{3} \times 12 \: months$

$\dashrightarrow \displaystyle \sf \: Time \: (T) = 2 \times 4 \: months$

$\dashrightarrow \underline{ \boxed{\displaystyle \sf \: \bold{Time \: (T) = 8 \: months}}}$