Question

please answer fast....​

Answer 1

$\frac{AD}{DB } = \frac{AE}{EC}$

$\frac{x}{x - 3} = \frac{x + 3}{x - 2}$

$x(x - 2) = (x - 3)(x + 3)$

${x}^{2} - 2x = {x}^{2} - {3}^{2}$

${x}^{2} - {x}^{2} - 2x = - {3}^{2}$

$- 2 {x}^{2} = - {3}^{2}$

$2x = 3$

$x = \frac{3}{2}$

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