Question

please ANSWER fast.................

Answer 1

We know that if a + b + c = 0 , then a^3 + b^3 + c^3 = 3xyz.

Given Equation is in the form of a^3 + b^3 + c^3.

= > (a^3)^1/3 + (b^3)^1/3 + (c^3)^1/3 = 3(a^1/3) * (b^1/3) * (c^1/3)

= > a + b + c = 3(abc)^1/3.

On cubing both sides, we get

= > (a + b + c)^3 = (3(abc)^1/3)^3

= > (a + b + c)^3 = 27abc.


Hope this helps!

Answer 2

Hi,

Please see the attached file!


Thanks