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May this helps u.....!
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DramaticEye905:
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X+y+z=0
X ^3+y^3+z^3=3xyz
=(3[a^2-b^2][b^2-c^2][c^2-a^2])/3(a-b)(b-c)(c-a)
=[(a-b)(a+b)(b-c)(b+c)(c-a)(c+a)]/(a-b)(b-c)(c-a)
=(a+b)(b+c)(c+a)
X ^3+y^3+z^3=3xyz
=(3[a^2-b^2][b^2-c^2][c^2-a^2])/3(a-b)(b-c)(c-a)
=[(a-b)(a+b)(b-c)(b+c)(c-a)(c+a)]/(a-b)(b-c)(c-a)
=(a+b)(b+c)(c+a)
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