Question

please answer fast ​

Answer 1

Answer:

$y^{2} + \frac{9}{y^2} - 6$

Step-by-step explanation:

$[y-\frac{3}{y}]^{2}$

⇒ $y^{2} + [\frac{3}{y}] ^{2} - 2[ y (\frac{3}{y})]$

⇒ $y^{2} + \frac{9}{y^2} - 6$

Hope it helps