Question

please answer fast....​

Answer 1

Answer:

$\tt2 \: log_{6} {}^{2} + 3 \: log_{6} {}^{3} + log_{6} {}^{12}$

Answer 2

Answer:

3+log2(with base 6)

Step-by-step explanation:

2log2+3log3+log12 (with base 6)

= log(2^2)+log(3^3)+log(6×2)

=log4+log9+log6+log2

=log(4×9×2)+log6 (log6 with base 6 is 1)

=log(6×6×2)+1

=log6+log6+log2+1

=1+1+log2(with base 6)+1

=3+log2(with base 6)