Question

please answer fast 8,9 questions

Answer 1

9. We know sum of all the angles of triangle =180°
Let angle p be x
So according to question
angle p is 2 times the q
or angle q=1/2x
And angle r = 3 times of q
or angle r = 3/2x
Sum of all the angle =180°
so,
180°= x+1/2x+3/2x
180=3x
x=60°
So Angle
P=60
Q=30°
R=90°

Question 10
Angle of triangle are in ratio 1:4:5
let the angle be x:4x:5x
Sum of all the angle of triangle=180°
180°=x+4x+5x
10x=180°
x=18°

So angle are
x=18°
4x=4*18°=72°
5x=5*18°=90°

Question 8
Here we use exterior angle prop:

In ∆ABD
angle DAB+ angle ABD=96°

let angle ABD=x

But angle ABD=3 *angle DAB
So angle DAB=3x

so we have Angle
ABD+BAD=96°
x+3x=96°
4x=96°
x=24°

So angle ABD=x=24°
And angle DAB=3x=3*24°=72°