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An image 2 times the size of the object is obtained with a convex lens of focal length 18cm. What are the possible positions of the object? Calculate the two possible distances of the object from the lens. Also calculate the image distance.
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Answer:
By using lens formula
v
1
−
u
1
=
f
1
where v=24cm ,f=18cm
24
1
−
u
1
=
18
1
from this we get u=−72cm
magnification of lens is m=
u
v
m=
−72
24
=−
3
1
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