Math, asked by radhakrishna1916, 1 month ago

please answer fast and correctly please​

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Answered by senboni123456
1

Step-by-step explanation:

Let the given matrix be

A =  \left[ \begin {array}{ccc}1 & - 1 &2 \\ 3 & 0 & 4 \\  - 4   & - 2 &5 \end{array} \right]

Now,

 \det{A } =  |A| =  \left|  \begin {array}{ccc}1 & - 1 &2 \\ 3 & 0 & 4 \\  - 4   & - 2 &5 \end{array} \right |

 \tt  \large{\red{ • \: R_{3} \to \: R_{3} - 2 R_{1}}}

 \implies  |A| =  \left|  \begin {array}{ccc}1 & - 1 &2 \\ 3 & 0 & 4 \\  - 4 - 2   & - 2 + 2 &5 - 4 \end{array} \right |

 \implies  |A| =  \left|  \begin {array}{ccc}1 & - 1 &2 \\ 3 & 0 & 4 \\  - 6   & 0 &1 \end{array} \right |

 \tt  \large{\red{ • \: Opening \:  \: along \:  \: C_{2}   }}

 \implies  |A| =  - ( - 1) \left|  \begin {array}{cc} 3  & 4 \\  - 6   &1 \end{array} \right |

 \implies  |A| =   1 \{3 - ( - 6).(4) \}

 \implies  |A| =    (3  + 24)

 \implies  |A| =   27

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