please answer fast and correctly.. question no. 19 please
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Answered by
1
let the no.of deer be a
according to question
1/2a are grazing.
from remaining (1/2) 3/4th are playing and
Rest means 1/4th=9
as,1/4th=9 eq.1
so,remaining 3/4th =27eq.2
so by adding eq.1 &2
we get,
1/2 th of the total deer =36
as 1/2 are grazing
then total no. of deer
=1/2+1/2
=36+36=72
so,the total no. of deer are 72
according to question
1/2a are grazing.
from remaining (1/2) 3/4th are playing and
Rest means 1/4th=9
as,1/4th=9 eq.1
so,remaining 3/4th =27eq.2
so by adding eq.1 &2
we get,
1/2 th of the total deer =36
as 1/2 are grazing
then total no. of deer
=1/2+1/2
=36+36=72
so,the total no. of deer are 72
Lolll:
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Answered by
5
According to given sum,
Let number of deer in the herd be x.
Then number of deer grazing = x/2
remaining deer = x/2
Number of deers playing = 3/4×x/2
=3x/8
Number of deers drinking water= 9
Number of deers = number of deers grazing + number of deers playing + number of deers drinking.
=> x =x/2+3x/8+9
=>x/8=9
=> x= 72 .
so, number of deers = 72
:-)Hope it helps u .
Let number of deer in the herd be x.
Then number of deer grazing = x/2
remaining deer = x/2
Number of deers playing = 3/4×x/2
=3x/8
Number of deers drinking water= 9
Number of deers = number of deers grazing + number of deers playing + number of deers drinking.
=> x =x/2+3x/8+9
=>x/8=9
=> x= 72 .
so, number of deers = 72
:-)Hope it helps u .
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