Math, asked by piyushbd28, 1 month ago

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The equation of the circle touching the y-axis at
the origin and passing through (b, c) is

(a) b (x^2 - y^2) = x (b^2 - c^2)
(b) b (x^2 - y^2) = x (b^2 + c^2)
(c) b (x^2 + y^2) = x (b^2+ c^2)
(d) b (x^2 + y^2) = x (b^2 - c^2)​

Answers

Answered by mdmamtadhoot
1

Step-by-step explanation:

The equation of a circle with centre at (h, k) and radius equal to a, is (x - h)2 + (y - k)2 = a2. When the circle touches y-axis i.e., h = a. If a circle touches the y-axis, then the x-co-ordinate of the centre will be equal to the radius of the circle.

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Answered by frag22
0

Answer:

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