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A rectangular room of dimension 8m x 6m x 3m is to be painted. If it costs ₹60 per square metre, find the cost of painting walls of the room.
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Dimension of a rectangular room = 8 m × 6 m × 3 m
Rate of painting = Rs. 60 per m²
For this purpose we have to calculate total surface area of rectanglular room.
Surface area of rectangular room = 2 ( 6 × 8 + 8 × 3 + 6 × 3 )
= 2 ( 48 + 24 + 18 )
= 2 ( 90 )
= 180 m²
Cost for painting = 180 × 60
= Rs. 10800
So the total cost of painting is Rs . 10,800
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Given Dimensions of room are:
⇒ Length = 6m.
⇒ Breadth = 6m.
⇒ Height = 3 m.
∴ Area of four walls of the room = 2h(l + b)
⇒ 2 * 3(8 + 6)
⇒ 6(14)
⇒ 84 m^2.
Given cost per m^2 = 60.
Cost of painting the walls of the room at the rate of 60 per m^2:
⇒ 84 * 60
⇒ 5040.
Therefore, cost of painting the walls of the room = 5040.
Hope it helps!
ganpat772076:
Thank you
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