Question

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Answer 1

Answer:

When h is 10m,

P.E = mgh= 10 ×10×10=1000J

K.E =0 J ( K.E at highest point is 0)

M.E = P.E+K.E = 1000J

When K.E is 1000J

P.E = 0J (P.E is minimum at lowest point)

M.E = 1000J

h = 0m(K.E is maximum at lowest point)

When P.E is 500J

M.E = 1000J (M.E always remains constant for a given system)

K.E = 500J

h=P.E/mg =5m

When h = 2m

P.E = mgh= 10×10×2=200J

K.E =800J

M.E=1000J