Question

Please answer fast and I need a meaningful answer. If you don't know. Don't answer and don't get free points.

Answer 1

firstly,make a ||gm say ABCD,and join the AC(diagonal)
now we get triangleABC,
as we know that area of parallelogram ABCD=b×h (1)
also we know that a diagonal divides a triangle in two triangles of equal area,area of triangle ABC=1/2 area of parallelogram ABCD
substituting the value of equation (1) here we get,
area of triangle ABC=1/2×(bh)
hence,we proved that area of a triangle area=1/2×b×h.

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Answer 2

Answer:

Step-by-step explanation:

firstly,make a ||gm say ABCD,and join the AC(diagonal)

now we get triangleABC,

as we know that area of parallelogram ABCD=b×h (1)

also we know that a diagonal divides a triangle in two triangles of equal area,area of triangle ABC=1/2 area of parallelogram ABCD

substituting the value of equation (1) here we get,

area of triangle ABC=1/2×(bh)

hence,we proved that area of a triangle area=1/2×b×h.

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