Question

Please answer fast and no irrelevant answers please ❤​

Answer 1

Step-by-step explanation:

$< abd = < bac + < acb \\ = > 3 {x}^{2} + 1 + 2x = 2 {x}^{2} + 1 + 3x + 6 \\ = > {x}^{2} - x - 6 = 0 \\ = > (x - 3)(x + 2) = 0 \\ so \: \: \: x = 3 \: or \: x = - 2 \\ \\ < abd = 3 {(3)}^{2} + 2 \times 3 + 1 = 34 \\ or \: < abd = 3 \times {( - 3)}^{2} + 2( - 3) + 1 \\ \: \: \: = 22 \\ \\ \\ so \: \: < abc = 180 - 34 = 146 \\ < abc = 180 - 22 = 158$

I hope it will help you to understand the solution ☺️