Math, asked by SAMIZAYN, 11 months ago

PLEASE answer fast.. best answer will be marked brailiest​

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Answered by grmr1968
1

HEY!!

In right triangle ABC  , by pythagoras theorem,

BC^2=AB^2+AC^2

=72+242 = 49 + 576 = 625

Therefore,BC^2=625

     BC=25

Now, ∠COD+∠BOD=180∘      ( since they are Linear pair angles )

    ∠COD = 180 - ∠BOD

⇒∠COD=180∘–90∘=90∘

Now, area of the shaded region = Area of sector having central angle                                                                   .                                                    360∘–90∘ – Area of triangle ABC

=270/360 . π(BC/2)^2  – 1/2(AB×AC)

=3/4×3.14(25/2)^2– 1/2×(7×24)

= 367.97 – 84 = 283.97 cm^2

There fore, the area of shaded region is 283.97 cm^2

HOPE IT HELPS .....


SAMIZAYN: bro but the question is how to show it right triangle(ABC)
grmr1968: once look at the question
grmr1968: the question is to find the area of the shaded region
SAMIZAYN: but dear u cannot tell them directly it is right ∆ u must prove them
grmr1968: the angle subtended by a semicircle is half the angle at the centre. the angle in the semicircle is 90 degree
BAC=90 degree
so, that triangle ABC is a right angle triangle.
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