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HEY!!
In right triangle ABC , by pythagoras theorem,
BC^2=AB^2+AC^2
=72+242 = 49 + 576 = 625
Therefore,BC^2=625
BC=25
Now, ∠COD+∠BOD=180∘ ( since they are Linear pair angles )
∠COD = 180 - ∠BOD
⇒∠COD=180∘–90∘=90∘
Now, area of the shaded region = Area of sector having central angle . 360∘–90∘ – Area of triangle ABC
=270/360 . π(BC/2)^2 – 1/2(AB×AC)
=3/4×3.14(25/2)^2– 1/2×(7×24)
= 367.97 – 84 = 283.97 cm^2
There fore, the area of shaded region is 283.97 cm^2
HOPE IT HELPS .....
SAMIZAYN:
bro but the question is how to show it right triangle(ABC)
BAC=90 degree
so, that triangle ABC is a right angle triangle.
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