Physics, asked by mayrasingh, 1 year ago

please answer fast c part

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Answered by sssrohit005p4c0ey
1
Work done in bringing q1 from infinity to r1against the external field = q1V(r1)

Work done in bringing q2 from infinity to r2against the external field= q2V(r2)

Work done on q2 against the force exterted by q1 = 1/4πεo.(q1q2/r12)

Here, r12 is the distance between q1 and q2.

So, the total potential energy of the system= The work done in assembling the two charges

U= q1V(r1)+q2V(r2)+1/4πεo.(q1q2/r12)

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