please answer fast c part
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Work done in bringing q1 from infinity to r1against the external field = q1V(r1)
Work done in bringing q2 from infinity to r2against the external field= q2V(r2)
Work done on q2 against the force exterted by q1 = 1/4πεo.(q1q2/r12)
Here, r12 is the distance between q1 and q2.
So, the total potential energy of the system= The work done in assembling the two charges
U= q1V(r1)+q2V(r2)+1/4πεo.(q1q2/r12)
Work done in bringing q2 from infinity to r2against the external field= q2V(r2)
Work done on q2 against the force exterted by q1 = 1/4πεo.(q1q2/r12)
Here, r12 is the distance between q1 and q2.
So, the total potential energy of the system= The work done in assembling the two charges
U= q1V(r1)+q2V(r2)+1/4πεo.(q1q2/r12)
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